Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
5. Geometric Sequences
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Exercise 40 Page 311

Practice makes perfect
a We see that the first figure is just a triangle. The second figure is a triangle divided into 4 small triangles, and the third triangle is divided into 16 small triangles.

The number of small triangles for each figure is 4 times that of the previous figure. Hence, there is a common ratio of 4. The number of triangles is 1 for the first figure. We can write the function since a_1= 1 and r= 4. f(n)= a_1( r)^(n-1) ⇔ f(n)= 1( 4)^(n-1) The function f(n)=4^(n-1) gives the number of small triangles in the large triangle for the nth figure.

b Using the function in Part A, we can find the number of small triangles for the 10th figure.
f(n)=4^(n-1)
f( 10)=4^(10-1)
â–Ľ
Simplify right-hand side
f(10)=4^9
f(10)=262 144
The 10th figure will be a large triangle containing 262 144 small triangles.