5. Geometric Sequences
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The number of small triangles for each figure is 4 times that of the previous figure. Hence, there is a common ratio of 4. The number of triangles is 1 for the first figure. We can write the function since a_1= 1 and r= 4. f(n)= a_1( r)^(n-1) ⇔ f(n)= 1( 4)^(n-1) The function f(n)=4^(n-1) gives the number of small triangles in the large triangle for the nth figure.