body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

1. Writing and Graphing Inequalities

Continue to next subchapter

Exercise 60 Page 60

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

x=1

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. In this case, we start by subtracting 2 from both sides of the equation.

x+2=3

LHS-2=RHS-2

x+2-2=3-2

Subtract term

x=1

The solution to the equation is x=1. We can check our solution by substituting it into the original equation.

x+2=3

x= 1

1+2? =3

Add terms

3=3

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Communicate Your Answer p.53

Monitoring Progress p.54-57

Exercises p.58-60