We are told that the area A of the given rectangle is greater than 12 square inches.
A > 12in.^2
Recall the formula for the area of a rectangle.
A=l w
Here, l is the length and w is the width of the rectangle. Let's substitute this expression for A in our inequality.
l w>12in.^2
We are also given the length of the rectangle, l= x, and the width, w= 2. If we substitute these values into our inequality, we will be able to solve for the missing dimension.
This inequality tells us that, for the area of a rectangle with width 2 inches to be greater than 12in.^2, the length must be greater than 6 inches.
x>6in.