Big Ideas Math Algebra 2, 2014
BI
Big Ideas Math Algebra 2, 2014 View details
8. Using Sum and Difference Formulas
Continue to next subchapter

Exercise 5 Page 523

Rewrite 23π12 as 2π- π12. Then, use the Angle Difference Formula for a sine. To find the value of the sine of π12, rewrite π12 as π3- π4. Then, use the Angle Difference Formula.

sqrt(2)-sqrt(6)/4

Practice makes perfect

Before we rewrite the given expression, let's start by recalling the values of the three main trigonometric functions for the most important angles.

sin θ cos θ tan θ
θ =0 0 1 0
θ =π/6 1/2 sqrt(3)/2 sqrt(3)/3
θ =π/4 sqrt(2)/2 sqrt(2)/2 1
θ =π/3 sqrt(3)/2 1/2 sqrt(3)
θ =π/2 1 0 -
θ =π 0 - 1 0
θ =2π 0 1 0
Let's now recall the Angle Difference Formula for a sine. sin ( A- B)=sin Acos B-cos A sin B We will use this identity to rewrite the given expression.
sin 23Ď€/12
sin (2Ď€-Ď€/12)
sin 2πcos π/12-cos 2π sin π/12
Next, we will use the table we constructed at the beginning of this solution to simplify this expression. sin 2π cos π/12- cos 2π sin π/12 = ( 0) cos π/12-( 1) sin π/12 Let's simplify the obtained expression!
( 0) cos π/12-( 1) sin π/12
â–Ľ
Simplify
0-(1) sin π/12
0- sin π/12
- sin π/12
Therefore, we found that sin 23π12 = - sin π12. Be aware that π12 is the difference of π3 and π4. Therefore, we can rewrite sin π12 as the sine of a difference. sin π/12=sin (π/3-π/4) We can once again use the Sine Difference Formula to find the exact value of the expression.
sin π/12
sin (Ď€/3-Ď€/4)
sin π/3cos π/4-cos π/3 sin π/4
Next, we will use the table we constructed at the beginning of this solution to simplify this expression. sin π/3 cos π/4- cos π/3 sin π/4 = ( sqrt(3)/2) sqrt(2)/2-( 1/2) sqrt(2)/2 Let's finally simplify the obtained expression!
(sqrt(3)/2) sqrt(2)/2-(1/2) sqrt(2)/2
â–Ľ
Simplify
sqrt(3)* sqrt(2)/2* 2-1* sqrt(2)/2* 2
sqrt(3)* sqrt(2)/2* 2-sqrt(2)/2* 2
sqrt(3* 2)/2* 2-sqrt(2)/2* 2
sqrt(6)/4-sqrt(2)/4
sqrt(6)-sqrt(2)/4
Therefore, sin π12= sqrt(6)-sqrt(2)4. We can finally use this information to calculate our original expression.
sin 23π/12=- sin π/12
sin 23Ď€/12=- sqrt(6)-sqrt(2)/4
sin 23Ď€/12=- (sqrt(6)-sqrt(2))/4
sin 23Ď€/12=- sqrt(6)+sqrt(2)/4
sin 23Ď€/12=sqrt(2)-sqrt(6)/4