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| 10 Theory slides |
| 12 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Zain and Jordan planned an adventure across a vast desert landscape. They will cycle for three days until they reach a huge music festival! The first two days, Zain and Jordan need to cycle the same distance each day. On the third day, they will have 10 miles remaining to be cycled.
The total distance Zain and Jordan cycle during the trip is 60 miles. If they miscalculate their trip, they will miss the festival!
Equations can be named according to the minimum number of inverse operations needed to solve them.
LHS+3=RHS+3
Add terms
LHS/2=RHS/2
ca⋅b=ca⋅b
Calculate quotient
Identity Property of Multiplication
Zain and Jordan are cycling along. Already on their first day, they ran into a problem! Zain's tire got a terrible flat and they do not have a spare to replace it. They need to buy a new tire.
They head into town to buy extra tires to be better prepared.
LHS/3=RHS/3
Cross out common factors
Cancel out common factors
Calculate quotient
undoeach other. Consider the given equation. Here, the variable m is divided by 2 and then 5 is added to the result.
On the second day of this ride to the festival, Zain and Jordan begin to wonder about some of the data from their ride.
LHS⋅-45=RHS⋅-45
Commutative Property of Multiplication
ba⋅ab=1
a⋅cb=ca⋅b
Multiply
-b-a=ba
Calculate quotient
LHS−x=RHS−x
Subtract terms
LHS⋅(-1)=RHS⋅(-1)
-a(-b)=a⋅b
ca⋅b=ca⋅b
x=30
ca⋅b=ca⋅b
Multiply
Calculate quotient
Subtract term
Solve the equations by using the Properties of Equality. If necessary, give answers as decimals rounded to two decimal places.
Zain and Jordan continued cruising along their cycling trip. The beauty of the ride became even more noticeable as they could hear songbirds! Some birds sang perched atop a power line.
A few more birds flew in and joined the flock. As a result, the number of birds doubled. Then, 4 birds flew away. In the end, 8 birds were left singing on the power line.
LHS/2=RHS/2
Cross out common factors
Cancel out common factors
Calculate quotient
Zain and Jordan successfully reached the music festival! The line to enter the festival is super long. Each came up with their own way to describe the difference between the time they expected to wait in line and the time they will actually have to wait.
LHS/2=RHS/2
Cross out common factors
Cancel out common factors
Calculate quotient
An equation that models the challenge presented at the beginning of this lesson can now be written and solved. Recall that Zain and Jordan planned to cycle the same distance for the first two days of their trip, and then cycle the remaining 10 miles on the last day.
Remember, the whole trip is 60 miles long. Making these calculations will ensure they make it to the festival on time!
LHS/2=RHS/2
Cross out common factors
Simplify quotient
Calculate quotient
Kriz wants to buy a new bicycle. Luckily, the one that they want is on sale for 20% off.
We are asked to write an equation that represents the bicycle's original price. First, let's represent the unknown quantity with a variable. Here, the unknown quantity is the bike's original price p. On sale, the bike is 20 % off, or in other words 15 cheaper. Then, the price of the bike on sale is p- 15 p, or 45p. 4/5p = Bicycle Sale's Price In addition, Kriz has a coupon. They can pay $50 less than the sales price of the bicycle. 4/5p - 50 = Price Kriz Pays We know that Kriz only needs to pay $350 for the bike. This lets us complete the equation. 4/5p - 50 = 350 This equation can help us find the original price of the bike. Note that we can write different equations, but they will all be equivalent to the equation we wrote. These equivalent equations can also be obtained by applying the Properties of Equality to the above equation.
LaShay noticed some birds sitting on a power line.
We want to write an equation that represents the given situation. We first represent the unknown quantity with a variable. Here, the unknown quantity is the original number of birds. We will call it b. We know that half of the birds stayed. Then, the number of birds that stayed on the power line is 12 b. 12 b = Number of Birds That Stayed on the Power Line After that, 4 more birds sat on the power line. The final number of the birds on the power line was 12b + 4. 12 b + 4 = Final Number of Birds on the Power Line We know that in the end, there were 10 birds on the power line. This lets us complete our equation. 12 b + 4 = 10 This equation can help us find the number of birds that were sitting on the power line in the beginning. Note that we can write different equations, but they will all be equivalent to the equation we wrote. These equivalent equations can also be obtained by applying the Properties of Equality to the above equation.
Tearrik went shopping for new shoes. He noticed that the shoes he wanted were on a big sale and were 50% off!
We want to write an equation that represents the given situation. First, let's represent the unknown quantity with a variable. Here, the unknown quantity is the original price of the shoes. We will call it p. We know that the shoes are 50 % off. Then, the price of the shoes on sale is 12 p. 12 p = Shoe's Sales Price We know that Tearrik paid $45 less than the regular price of the shoes. This means that the price of the shoes on sale is equal to p- 45 . This lets us complete the equation. 1/2p = p- 45 This equation can help us find the original price of the shoes. Note that we can write different equations, but they will all be equivalent to the equation we wrote. These equivalent equations can also be obtained by applying the Properties of Equality to the above equation.
Vincenzo is training to be a faster runner.
We want to write an equation that represents the given situation. We first represent the unknown quantity with a variable. Here, the unknown quantity is the original time it took Vincenzo to run 100 yards. We will call it t. t = Vincenzo's time before he started training We know that Vincenzo improved his time by a sixth. In other words, his time after training is 56 his time before the training, or 56 t. 56 t = Vincenzo's time after training We also know that Vincenzo's improved time is 2 seconds faster than his original time. This tells us that it can be expressed as t - 2. Now we can write an equation. 56 t = t - 2 This equation can help us find Vincenzo's time before he started training. Note that we can write different equations, but they will all be equivalent to the equation we wrote. These equivalent equations can also be obtained by applying the Properties of Equality to the above equation.