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| 19 Theory slides |
| 13 Exercises - Grade E - A |
| Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
Prisms can be categorized by the shape of their bases. For example, a prism with a triangular base is called a triangular prism. A rectangular prism, on the other hand, has a rectangular base.
Determine whether the given solid is a triangular prism, a rectangular prism, or neither.
There are two important characteristics that give information about 3D objects.
The volume of a solid is the measure of the amount of space inside the solid. It is the three-dimensional equivalent of the area of the figure. Volume is measured using cubic units, such as cubic meters, or m3. The applet below illustrates the volume of some solids. Move the slider to fill the solids.
The surface area SA of a three-dimensional shape is the total area of all the surfaces of the shape. The lateral area LA is the total area of all lateral surfaces, the surfaces of the shape that are not bases. Lateral area can be defined for polyhedrons, cones, and cylinders. In these instances, the surface area of the shape can be calculated by the formula below.
The net of a solid can be helpful to visualize the surfaces of a three-dimensional figure.
Consider a prism with a base area B and height h.
The volume of the prism is calculated by multiplying the base's area by its height.
V=Bh
By Cavalieri's principle, this formula holds true for all types of prisms, including skewed ones.
Recall that the volume of a solid is the measure of the amount of space inside the solid. Note that the top and bottom faces of the prism are always the same and parallel to each other.
Additionally, the prism is, so to speak, filled
with identical base areas that are stacked on top of each other to the height of the prism.
Consider a prism with a height h, base area B, and base perimeter P.
The surface area of the prism is the sum of the two base areas and the lateral area, which can be calculated as the product of the base perimeter and the height of the prism.
SA=2B+Ph
Note that although this proof is written for a regular prism, it is also true for a non-regular prism.
It is possible to derive two specific formulas for the volume and surface area of a rectangular prism.
Consider a rectangular prism with a width w, length ℓ, and height h.
The volume of the prism is calculated by multiplying the area of the base by the height of the prism.
V=wℓh
Consider a rectangular prism with a height h, base area B, and base perimeter P.
The surface area of the rectangular prism can be found using the following formula.
SA=2(wℓ+hℓ+hw)
P=2(w+ℓ), B=wℓ
Distribute h
Factor out 2
Consider a cube with a side length s.
The volume V of the cube can be calculated by raising the side length s to the power of 3, or cubing
it.
V=s3
Consider a cube with a side length s.
The surface area of the cube is given by the following formula.
SA=6s2
Substitute values
a⋅a=a2
Add terms
Substitute values
Multiply
Add terms
Multiply
Find the width of the prism by using the known volume of the prism and the formula for the volume of a rectangular prism. Then, use the formula for the surface area of a rectangular prism.
Substitute values
Multiply
Commutative Property of Multiplication
Rearrange equation
LHS/2.8=RHS/2.8
Use a calculator
Substitute values
Multiply
Add terms
Multiply
b=7, h=2.3
Multiply
b1⋅a=ba
Calculate quotient
Substitute values
Multiply
Add terms
Use the formula for the surface area of a prism and the given surface area to find the height of the prism. Then, find the volume of the prism.
b=4, h=2.7
Multiply
b1⋅a=ba
Calculate quotient
Substitute values
Multiply
LHS−10.8=RHS−10.8
Rearrange equation
LHS/11.5=RHS/11.5
Calculate the volume or surface area of the triangular or rectangular prism given the base area B, the height, and the side length of the base. The base is always a regular polygon. Round the answer to one decimal place if necessary.
Use the general formula for the volume of a prism to calculate the volume of the triangular prism. Then, use the formula for the volume of a rectangular prism to find the volume of the rectangular prism. Compare the volumes.
There are two possible shapes of the dog house for Bubbles. To determine which one offers the most space for the dog, each of their volumes should be calculated.
h=1, b=1.2
1⋅a=a
b1⋅a=ba
Calculate quotient
Finally, the volumes of the prisms can be compared.
Volume of the Triangular Prism | Volume of the Rectangular Prism |
---|---|
1.2 in.3 | 1.6 in.3 |
The volume of the rectangular prism is greater than the volume of the triangular prism. This means that the dog house in the shape of the rectangular prism is more spacious, so Mark should choose that one.
Izabella made a figure by placing a cube with 11-centimeter sides on top of another cube with 13-centimeter sides.
We are given the following figure and are asked to find the surface area. Let's start by analyzing the diagram.
The figure consists of two cubes. We can find their surface areas to get the desired area to be painted. However, notice that the smaller cube's lower base is adjacent to part of the larger cube's upper base. This means that the figure's surface area does not include the area of the smaller cube's lower base and an equally large part of the larger cube's upper base.
The surface area of the figure is the surface area of the smaller cube plus the surface area of the larger cube minus twice the area of the smaller cube's base. Let's find these areas one at a time, starting with the smaller cube. Recall that the surface area of a cube with a side length s can be calculated by using the following formula. S = 6s^2 Let's substitute 11 for s into the formula and find the surface area of the smaller cube.
The surface area of the smaller cube is 726 square centimeters. Next, let's calculate the surface area of the larger cube. This time, s will equal 13.
The surface area of the larger cube is 1014 square centimeters. Finally, we will calculate the area of the smaller cube's base, which is a square with the side length of 11 centimeters.
We can do this by squaring the side length of 11 centimeters. \begin{gathered} A_\text{square}={\color{#0000FF}{11}}^2={\color{#FF0000}{121}}\text{ cm}^2 \end{gathered} Now we can calculate the total surface area of the figure, which is the surface area of the smaller cube plus the surface area of the larger cube minus twice the area of the smaller cube's base. \begin{gathered} S_\text{figure} = {\color{#A800DD}{726}} + {\color{#FF00FF}{1014}} - 2 \times{\color{#FF0000}{121}} = 1498\text{ cm}^2 \end{gathered} The total surface area of the figure to be painted is 1498 square centimeters.
A school locker at Harmony High School has the shape of a rectangular prism with a height of 26 inches, width of 12 inches, and length of 14 inches.
We are given the dimensions of the school locker in a shape of a rectangular prism.
We want to determine how much the surface area of the locker increase if the height of the locker were increased by 2 inches. To do so, we can calculate the surface area of the locker both before and after increasing the height.
Remember that surface area is the total area of all the surfaces of a three-dimensional figure. Let's begin by recalling the formula for the surface area of a rectangular prism. S=2(wl+hl+wh) We can substitute w= 12, l= 14, and h= 26 into the formula and evaluate S. Let's do it!
We found that the surface area of the original locker is 1688 square inches.
The height of the locker increases by 2 inches. Let's add 2 to the initial height to find the new one. h=26+2=28inches Now we can substitute w= 12, l= 14, and h= 28 into the surface area formula to find the surface area of the taller locker.
The surface area of the taller locker is 1792 square inches.
Finally, we will find the difference between the increased surface area and the original surface area. 1792-1688=104 in^2 Therefore, the surface area of the locker increased by 104 square inches.
We are asked to find the decrease in volume of the locker after the decrease in its length. Let's begin by remembering the formula for the volume of a rectangular prism. V=wl h We can find the original volume of the locker by substituting w= 12, l= 14, and h= 26 into the formula. After the length of the locker is decreased, the new length would be 14-2= 12 inches. Let's use these values to find both the original and decreased volumes.
Original Locker | Shallower Locker | |
---|---|---|
Dimensions | w= 12, l= 14, h= 26 | w= 12, l= 12, h= 26 |
Substitute | V_\text{or}=({\color{#0000FF}{12}})({\color{#009600}{14}})({\color{#A800DD}{26}}) | V_\text{dec}=({\color{#0000FF}{12}})({\color{#FD9000}{12}})({\color{#A800DD}{26}}) |
Multiply | V_\text{or}=4368 | V_\text{dec}=3744 |
Now that we know both volumes, we can calculate their difference. 4368-3744=624in^3 Therefore, the volume of the locker would decrease by 624 cubic inches.