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| | 12 Theory slides |
| | 12 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
The applet shows two different equations for the same line.
In the standard form of a line all x- and y-terms are on one side of the linear equation or function and the constant is on the other side.
Ax+By=C
In this form, A, B, and C are real numbers. It is important to know that A and B cannot both be 0. Different combinations of A, B, and C can represent the same line on a graph. It is preferred to use the smallest possible whole numbers for A, B, and C and it is also better if A is a positive number.
The given linear equation shows the relationship between the variables x and y. Determine if the equation is written in standard form.
A linear function written in standard form has quickly identifiable x- and y-intercepts. Since two points determine a line, this provides enough information to graph the function. Consider the following linear equation written in standard form. 3x+5y=30 The graph of this function can be drawn in two steps.
y= 0
Zero Property of Multiplication
Identity Property of Addition
.LHS /3.=.RHS /3.
The x-intercept is (10,0). The y-intercept can be found in a similar way. Substitute x= 0 into the equation and solve for y.
x= 0
Zero Property of Multiplication
Identity Property of Addition
.LHS /5.=.RHS /5.
The y-intercept is (0,6). rc Equation: & 3x+5y = 30 x-intercept: & (10,0) y-intercept: & (0,6)
| Assumption | x-intercept | y-intercept |
|---|---|---|
| A≠ 0, B≠ 0 | (C/A,0) | (0,C/B) |
| A= 0, B≠ 0 | The line is horizontal, y= C B, so it does not cross the x-axis. | (0,C/B) |
| A≠ 0, B= 0 | (C/A,0) | The line is vertical, x= C A, so it does not cross the y-axis. |
Tearrik is excited to buy school supplies. He plans to buy some cool pencils and notebooks.
The pencils he wants cost $2 each, and the notebooks he likes cost $5 each. He has $ 20 to spend. The following linear equation models this situation. 2x+5y=20 In this equation, x represents the number of pencils and y represents the number of notebooks.
2x+5y=20 Begin by finding the x-intercept. Substitute 0 for y and solve the equation for x.
y= 0
Zero Property of Multiplication
Identity Property of Addition
.LHS /2.=.RHS /2.
The point (10,0) is the x-intercept. Next, the y-intercept will be found. Substitute 0 for x and solve for y.
x= 0
Zero Property of Multiplication
Identity Property of Addition
.LHS /5.=.RHS /5.
The y-intercept is (0,4).
rc Equation: & 2x+5y = 20 [0.5em] x-intercept: & (10,0) [0.5em] y-intercept: & (0,4) Plot the intercepts on a coordinate plane. Then, connect the intercepts with a line.
The number of stationery purchased cannot be negative. In other words, stores do not sale a negative amount of products. This means that only positive values of x and y is considered in this context.
First, the x-intercept means that if Tearrik does not buy any notebooks, he can buy 10 pencils with all of his money. Whereas, the y-intercept means that if Tearrik does not buy pencils, he can buy 4 notebooks using all of his money.
Any linear equation can be rewritten in standard form. Consider the following linear equation that is written in slope-intercept form. y = 4/5x + 2/3 Using the Properties of Equality, the equation can be rewritten in standard form. Ax+By=C Here, A, B, and C are real numbers and A and B cannot both be equal to 0. It can be noted that representing A, B, and C with the smallest possible integers is preferred, as well as A being positive.
LHS * 15=RHS* 15
Distribute 15
Commutative Property of Multiplication
a/c* b = a* b/c
a/b=.a /5./.b /5.
a/b=.a /3./.b /3.
a/1=a
Multiply
Since a positive coefficient for x is preferable, the equation can be multiplied by - 1.
This equation is now in the standard form. Note that the values of A, B, and C are in their smallest possible integer forms.
Tearrik wanted to remember some mathematical contexts before going back to school. He wants to remember slope-intercept form and standard form of a line. This is why he wrote an equation in slope-intercept form. y=4x-8
y=4x-8 Remember that all x- and y-terms should be on one side of the linear equation and the constant should be on the other side in standard form. In addition to this, the coefficient of x should be positive when writing the equation in standard form.
LHS-y=RHS-y
Subtract terms
LHS+8=RHS+8
Commutative Property of Addition
Add terms
Rearrange equation
The standard form of the equation is written. c|c Slope-Intercept Form of a Line & Standard From of a Line y=4x-8 & 4x-y=8
The x-intercept is (2,0). Next, find the y-intercept of the line by substituting 0 for x in the equation.
x= 0
Zero Property of Multiplication
Subtract terms
LHS * (-1)=RHS* (-1)
The y-intercept is (0,-8). Plot the intercepts on a coordinate plane. Then connect them with a line to graph the line.
Tearrik realizes at the stationery shop that the price of five pencil cases equals $ 10 less than the price of two school bags. The graph below shows the relationship between the price of the school bag and the price of the pencil case.
The y-intercept and the slope of the line is used to write the equation of the line in slope-intercept form. Let's first look at the y-intercept. Remember that the y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis.
The y-intercept of the line is 5. Now find the ratio of the change in y-values to the change in x-values to find the slope.
When the x-values increase by 2, y-values increase by 5. Slope&=changes iny-value/changes inx-value &⇓ Slope&=5/2 The value of the slope is the coefficient of variable x, and the y-intercept is the constant of the equation.
Substitute the values into the equation to write the equation of the graph in slope-intercept form. y&= mx+ n &⇓ y&= 52x+ 5
Ax+By=C Additionally, the coefficients of the variables do not equal 0 in the standard form of an equation and, the coefficient of x is greater than 0. Rearrange the terms in the equation written in Part A to write it in standard form.
LHS * 2=RHS* 2
a*b/c= a* b/c
Cancel out common factors
Simplify quotient
LHS- 2y+10=RHS- 2y+10
Distribute -1
Commutative Property of Addition
Subtract terms
Rearrange equation
Note that the coefficients of the variables are 5 and -2 which are not equal to 0, and the coefficient of x is greater than 0. Here is the equation in standard form. 5x-2y=- 10
The standard form of a linear equation is written as follows. Ax+By= C In general, A, B, and C are real numbers. It is preferred for A, B, and C to be the smallest possible integers and for A to be positive. Find the values of A, B, and C by using the given line that has an equation in slope-intercept form. In the answers, make sure that A, B, and C are the smallest possible integers and that A is positive.
The following equation displays the relationship between the variables x and y in slope-intercept form. Rewrite the equation in slope-intercept form in standard form.
In this lesson, the standard form of a line has been discussed, recognized, graphed, and applied to real-world examples. Ax+By=C In this form, A, B, and C are real numbers. The preferred properties for these numbers are as follows.
The number of equations in standard form that meets these properties is exactly one for each line. However, there are infinitely many equivalent equations in standard form. In other words, linear equations that describe the same line are equivalent. These equivalent equations can be written by using the Multiplication Property of Equality.
Which of the following linear equations are in standard form? Select all that apply.
We can recall the standard form of a linear equation. Ax+ By= C In this form, A, B, and C are real numbers and A and B cannot both equal 0. With this information, we can conclude that two of the given equations are written in standard form. 7x+ 5y&= 6 8x+ 9y&= 40
The following equation is written in slope-intercept form. y=2/4x-5 Rewrite the equation in standard form.
We want to rewrite the equation in standard form. Let's first recall the standard form of a line. Ax+ By= C In this form, A, B, and C are real numbers and A and B cannot both equal 0. Remember that the value of A should be positive. Let's rearrange the equation in standard form.
Standard form of the given equation is 2x-4y=20.
We substitute 2 for y. Then we can solve the equation for x by isolating it.
When y is 2, x is equal to 4.
We will substitute 4 for x and solve the equation for y.
The value of y is -3.
Choose the correct option that shows the x- and y-intercepts of the given equation. 13x-2y=52
Remember that the x-intercept of a line is the x-coordinate of the point where the line crosses the x-axis. The ordered pair of the point where the line crosses the x-axis is denoted as ( x, 0). This is why we substitute 0 for y and solve the equation for x to find the x-intercept.
The equation intercepts the x-axis at x=4. Similar to finding the x-intercept, the y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis. The ordered pair of the point where the line crosses the y-axis is denoted as ( 0, y). This is why we substitute 0 for x and solve the equation for y to find the y-intercept.
The equation intercepts the y-axis at y=-26.
Take a look at the following equation that is written in standard form. 4x+5y=20 Which of the graphs correctly represents this equation?
Let's begin by finding the x- and the y-intercepts of the linear equation. 4x+5y=20 We will substitute 0 for y and solve the equation for x to find the x-intercept.
The x-intercept of a line is the x-coordinate of the point where the line crosses the x-axis. The y-coordinate of the point is equal to 0. This means that we should substitute 0 for y to find the x-intercept of the given equation. Then, solve for x.
An x-intercept of 5 means that the graph passes through the x-axis at the point ( 5,0).
Similarly, the y-intercept of a line is the y-coordinate of the point where the line crosses the y-axis. The x-coordinate of the point at the y-intercept is 0. Therefore, we will substitute 0 for x to find the y-intercept.
A y-intercept of 4 means that the graph passes through the y-axis at the point (0, 4).
We found the x- and y- intercepts of the equation.
| x-intercept | (5,0) |
|---|---|
| y-intercept | (0,4) |
We can now graph the equation by plotting the intercepts and connecting them with a line.
This graph corresponds to option A.
Emily loves to stay active and challenge herself with physical activities. She decided to go on an adventure where she would both bike and run a total distance of 80 kilometers. Emily sets a goal for herself to bike for 5 hours and run for 3 hours. This real world situation is modeled by the following equation in standard form. 5x+3y=80 In this equation, Emily's speed while biking is represented by x and Emily's speed while running is represented by y. Find Emily's speed while biking if her speed while running is 5 kilometers per hour.
We model the relationship between time and distance for Emily's adventure by using the standard form of a line. 5x+3y=80 We are given that Emily's speed while running is 5 kilometers per hour. We substitute 5 for y — the variable that represents Emily's speed while running.
Emily's speed while biking is 13 kilometers per hour.