Let b be the amount of blue paint he uses in the mix and y be the amount of yellow paint. Since he needs to make a total of 21 gallons of green paint, we can write the first equation as follows.
b+y=21
We also know that he must use 2.5 times more blue paint than yellow paint in the mix. We can write this as b=2.5y. If we combine the equations, we have the following .
{b+y=21b=2.5y
To find how much blue and how much yellow paint he uses in the mix, we have to solve the system
{b+y=21b=2.5y(I)(II)
for b and y. Since b is already isolated in Equation (II), we will substitute 2.5y for b in Equation (I) and solve the resulting equation for y. b+y=21
2.5y+y=21
3.5y=21
y=6
Thus, Marcel must use 6 gallons of yellow paint in the mix. Now, let's substitute 6 for y in Equation (II) to find b.
Thus, we have found that Marcel must use 15 gallons of blue paint in addition to the 6 gallons of yellow paint to make 21 gallons of green paint.