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{{ printedBook.courseTrack.name }} {{ printedBook.name }} We want to solve the system ${6y=x5x−y=31 (I)(II) $ using the substitution method. When solving a system of equations using substitution, there are three steps.

- Isolate a variable in one of the equations.
- Substitute the expression for that variable into the other equation and solve.
- Substitute this solution into one of the equations and solve for the value of the other variable.

$5x−y=31$

Substitute$x=6y$

$5⋅6y−y=31$

MultiplyMultiply

$30y−y=31$

SubTermSubtract term

$29y=31$

DivEqn$LHS/29=RHS/29$

$y=2931 $

$6y=x$

Substitute$y=2931 $

$6⋅2931 =x$

MoveLeftFacToNum$a⋅cb =ca⋅b $

$296⋅31 $

MultiplyMultiply

$29186 =x$

RearrangeEqnRearrange equation

$x=29186 $