We can solve the system by substituting one equation into the other.
Now, we have a . Its solutions will give us the
-values for the solutions of the system. Let's rearrange the equation so that it is set equal to
From here, we can solve the equation using the .
-values for the solutions are
Now, we substitute them into one of the original equations to find the corresponding
-values. We'll use the first equation, but it doesn't matter which.
Thus, the solutions to the quadratic system are