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| Student Learning Objectives: |
|---|
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| | 11 Theory slides |
| | 6 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
In the following applet, four figures are shown. One of the three figures at the bottom is the result of applying a rigid motion or a sequence of rigid motions to the upper figure. Match the preimage with its image.
When working with the different types of rigid motions, it was used that they map a segment into another segment. To verify that this is true, consider a segment AB and any rigid motion. Let C be the image of A and D the image of B.
Because rigid motions preserve distances, CD is equal to AB. Now, to check that every point of AB was actually mapped onto CD, consider a point P on AB different from the endpoints. Let Q be the image of P under the rigid motion.
The idea is to show that Q lies on CD between C and D. To do this, it must be checked that CQ+QD is equal to CD. Again, since rigid motions preserve distances, CQ=AP and QD=PB. CQ=AP & (I) QD=PB & (II) Next, Equations (I) and (II) can be added together and simplified using the Segment Addition Postulate.
(I): Add II
(I): Segment Addition Postulate
(I): AB= CD
Rigid motions map n-sided polygons onto n-sided polygons.
Consider a rigid motion and a circle C.
Since rigid motions preserve distances, the image of C is a circle whose radius is equal to the radius of C. Therefore, C' is the circle centered at P' and radius r.
The image of C is a circle centered at P' with radius PQ. Since PQ and P'Q' are equal, C' is the circle centered at P' passing through point Q'.
The image of C is a circle passing through A', B', and C'. Next, find the center of C' by drawing the perpendicular bisectors of A'B' and B'C'.
The point of intersection of the perpendicular bisectors is the center of C'. That way, the image of C can be drawn.
Since rigid motions map segments into congruent segments and angles into congruent angles, rigid motions can be used to define when a pair of geometric figures are congruent.
Two figures are congruent figures if there is a rigid motion or sequence of rigid motions that maps one of the figures onto the other. As a result, congruent figures have the same size and shape. To denote algebraically that two figures are congruent, the symbol ≅
is used.
ABCDE ≅ JKLMN or CDEAB ≅ LMNJK
Emily and her family are spending the weekend at a lake house. On Saturday afternoon, Emily begins to work on her geometry homework that asks her to determine if the following pair of polygons are congruent.
Unfortunately, Emily left her ruler and protractor at her house and only brought a pencil and a piece of tracing paper.
Then, draw one of the figures on tracing paper and translate it so that the corresponding vertices match each other.
Since the rest of the vertices do not match, a single translation is not enough to map one figure onto the other. The next step is to try to match a pair of corresponding sides. To do so, rotate the paper about the matching vertices.
As seen, the rest of the sides still do not match. Therefore, another transformation is needed. Notice that the two given polygons have opposite orientations, which suggests that performing a reflection is helpful. In this case, the line of reflection is the line containing the matching sides.
This time, all sides of both figures match.
When two figures are not congruent, no sequence of rigid motions maps one figure onto the other. Even so, it is possible that a rigid motion maps certain parts of the preimage onto their corresponding parts, but not all. For example, consider the following pair of quadrilaterals.
A translation can map AB onto PQ. However, the remaining parts of ABCD do not match the parts of PQRS. Equivalently, CD can be mapped onto RS by a translation. Still, the remaining parts do not match as before.
Consider the following pair of quadrilaterals ABCD and PQRS in the coordinate plane.
Furthermore, consider the following sequences of transformations.
Are the given quadrilaterals congruent?
In the affirmative case, which of the listed sequences maps ABCD onto PQRS?
At first glance, it seems like the two quadrilaterals have opposite orientations. If this is true, the first sequence cannot map ABCD onto PQRS because both translations and rotations maintain the orientation. To verify it, apply the sequence to ABCD.
Sequence 1 maps only AB onto PQ. The remaining parts do not match. Consequently, Sequence 1 does not map ABCD onto PQRS.
A glide reflection is the composition of a reflection and a translation performed in any order. Since a reflection is involved, this sequence is a good candidate. To apply it to ABCD, start with the reflection.
Next, the translation along v=⟨ 3,-3⟩ will be applied.
As can be seen, the given glide reflection mapped ABCD onto PQRS. Therefore, the given quadrilaterals are congruent.
Like the previous sequence, this third sequence also involves a reflection and thus it is a good candidate. Here, the rotation is applied first. Since it is a 180^(∘) rotation, the direction of the rotation will not affect the resulting image.
Next, reflect the resulting image across the line y=x.
As the diagram shows, this sequence does not map ABCD onto PQRS. As a result, only the second sequence of transformations maps ABCD onto PQRS.
In the following applet, the left-hand side polygon can be translated and rotated.
By applying these rigid motions, determine whether the given pair of polygons are congruent.
Because of copyright, in marketing, two different companies cannot have the same name or logo. Here, knowing how to determine if two figures are congruent is useful in dealing with intellectual property. Sometimes lesser-known brands use logos almost congruent to those of well-known brands. The intention is to receive instant recognition. For instance, consider the well-known logo of MathLeaks and the logo of a startup company called MathLovers.
Congruent figures are everywhere in daily life. For example, the figures formed by lines on one half of a basketball court are congruent to the figures formed on the other half. However, verifying this congruence through rigid motions is a difficult thing to do, given the circumstance of not being able to see the rigid motions occur.
The quadrilateral ABCD has undergone a sequence of rigid motions mapping it onto A'''B'''C'''D'''.
The following are the sequence of transformations. Some key information has been omitted. Translation:& (x,y)→ (x+8,y) [0.15em] Rotation:& by counterclockwise [0.1em] & about the origin Reflection:& in the line Select the correct rotation and line of reflection.
Let's begin by performing the first transformation. It is a translation of 8 units to the right.
Examining the diagram, we can decipher that A'B'C'D' is a reflection of the final image A'''B'''C'''D''' in the x-axis. Recall the formula for reflecting something in the x-axis. Reflection in thex-axis (x,y) → (x,- y) The reflection in the x-axis changes the sign of the y-coordinate. We need to replicate a reflection in the x-axis using a combination of transformations, one rotation and one reflection. Let's have a look at some rules for rotating something counterclockwise about the origin.
| Rotation | Rule |
|---|---|
| 90^(∘) | (x,y) → (- y,x) |
| 180^(∘) | (x,y) → (- x,- y) |
| 270^(∘) | (x,y) → (y,- x) |
We can see that a rotation of 180^(∘) changes the y-coordinate in the desired way. Therefore, let's perform this rotation.
Now we see that we need to perform a reflection in the y-axis, or x=0, to make A''B''C''D'' map onto A'''B'''C'''D'''.
Therefore, the transformations that are missing are a rotation of 180^(∘) counterclockwise about the origin and a reflection in x=0.