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The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc.
a=118, b=49, c=144, d=98
Consider the given diagram.
Let's find the values of a, b, c, and d one at a time.
The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc.
Since the inscribed angle — which measures 59^(∘) — intercepts the arc that measures a^(∘), we can say that 59 is half of a.
59=a/2 ⇔ a=118
Thus, the value of a is 118.
The sum of interior angles of a triangle is 180^(∘). Using this fact, we can find the value of b.
Let's add the angle measures of the triangle. b+59+72=180 ⇔ b=49
Thus, the value of b is 49.
By the Inscribed Angle Theorem, we can find the value of c.
Since the inscribed angle — which measures 72^(∘) — intercepts the arc that measures c^(∘), we can say that 72 is half of c.
72=c/2 ⇔ c=144
Therefore, the value of c is 144.
Earlier we found that b is 49^(∘). Notice that 49^(∘) is the inscribed angle intercepting the arc that measures d^(∘).
According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of its intercepted arc. This means that 49 is half of d.
49=d/2 ⇔ d=98
Therefore, the value of d is 98.