Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Chapter Review
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Exercise 16 Page 815

The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc.

a=118, b=49, c=144, d=98

Practice makes perfect

Consider the given diagram.

Let's find the values of a, b, c, and d one at a time.

Finding a

The Inscribed Angle Theorem states that the measure of an inscribed angle is half the measure of its intercepted arc.


Since the inscribed angle — which measures 59^(∘) — intercepts the arc that measures a^(∘), we can say that 59 is half of a. 59=a/2 ⇔ a=118

Thus, the value of a is 118.

Finding b

The sum of interior angles of a triangle is 180^(∘). Using this fact, we can find the value of b.

Let's add the angle measures of the triangle. b+59+72=180 ⇔ b=49

Thus, the value of b is 49.

Finding c

By the Inscribed Angle Theorem, we can find the value of c.

Since the inscribed angle — which measures 72^(∘) — intercepts the arc that measures c^(∘), we can say that 72 is half of c.

72=c/2 ⇔ c=144

Therefore, the value of c is 144.

Finding d

Earlier we found that b is 49^(∘). Notice that 49^(∘) is the inscribed angle intercepting the arc that measures d^(∘).

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of its intercepted arc. This means that 49 is half of d.

49=d/2 ⇔ d=98

Therefore, the value of d is 98.