Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Chapter Review
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Exercise 12 Page 814

Within a circle, chords equidistant from the center are congruent.

4.5

Practice makes perfect

Consider the given circle. We will find the value of x.

Let's call the chords in the diagram as AB and CD, and notice that AB and CD are equidistant from the center of the circle.


Recalling that chords equidistant from the center are congruent, we can determine CD.

AB=CD=9

Looking at the figure, we can see that x is half of the length of CD. Therefore, we can find the value of x by dividing the length of CD by 2.
x=CD/2
x=9/2
x=4.5

The value of x is 4.5.