Pearson Geometry Common Core, 2011
PG
Pearson Geometry Common Core, 2011 View details
Chapter Review
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Exercise 24 Page 816

(x+3)^2+(y+4)^2=25

Practice makes perfect
Let's start by recalling the standard form of an equation of a circle.

(x- h)^2+(y- k)^2= r^2 In this form, ( h, k) is the center of the circle and r is its radius. We are told that the center of the circle is ( - 3, - 4) and its radius is 5. This information is enough to write the equation. (x-( - 3))^2+(y-( - 4))^2= 5^2 ⇕ (x+3)^2+(y+4)^2=25