Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
2. Multiplying and Factoring
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Exercise 42 Page 496

Practice makes perfect
a Let's take a look at the given diagram.

The sides of a polygon are the line segments that make it up. We will highlight the sides of the polygon on the diagram.

By looking at the diagram, we can see that the polygon has six sides. Next, let's determine the number of diagonals coming from one vertex. A diagonal is a line segment that connects two vertices of a polygon, but it is not the polygon's side.

There are three diagonals coming from one vertex of the given polygon.

b

Examples

A diagonal is a line segment that connects two vertices of a polygon, but it is not the polygon's side. Let's take the given polygon as an example.

From Part A we know that this polygon is sided. In total there are five line segments coming from one vertex, one less than the number of the sides. Only of them are the diagonals. The remaining line segments make up the sides. Next, let's consider a sided polygon.

In total there are four line segments coming from one vertex, one less than the number of the sides. Again, line segments make up the sides. Therefore, diagonals are coming from one vertex.

Summary

Finally, let's consider one vertex of a polygon that has sides. In total there are line segments coming from one vertex, one less than the number of the sides. of these line segments make up the sides and the rest are the diagonals.
There are diagonals coming from one vertex of a polygon that has sides.
c The number of diagonals from all vertices of a polygon that has sides is We are asked to write this polynomial in standard form. To do so, let's use the Distributive Property.
d Use the formula from Part C. The number of diagonals from all vertices of a polygon that has sides is given by the following formula.
In our case the polygon has sides. Therefore, Let's substitute this value into the formula and simplify.
The polygon has diagonals.