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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

2. Multiplying and Factoring

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Exercise 46 Page 496

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

x=2

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality. In this case, the variable term is already on the left-hand side of the equation, so we will start by adding 11 to both sides of the equation.

7x-11=3

LHS+11=RHS+11

7x-11+11=3+11

Add terms

7x=14

.LHS /7.=.RHS /7.

7x/7=14/7

Calculate quotient

x=2

The solution to the equation is x=2.

Subchapter links

Lesson Check p.494

Practice and Problem-Solving Exercises p.495-496

Standardized Test Prep p.496

Mixed Review p.496