Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 17 Page 357

What do parallel lines have in common?

y=- x+8

Practice makes perfect
Consider the given equation of a line. y=- x+1 ⇔ y= - 1x+ 1 When lines are parallel, they have the same slope. With this, we know that all lines that are parallel to our given line will have the same slope of - 1. Knowing this, we can write a general equation in slope-intercept form for all the lines parallel to the given line. y= -x+ b In addition to being parallel, we need a line that passes through the point ( 4, 4). By substituting this point into the general equation for x and y, we will be able to solve for the y-intercept b of the parallel line.
y=- x+b
4=-( 4)+b
â–Ľ
Solve for b
4=- 4+b
8=b
b=8
Now that we have the y-intercept, we can write the parallel line to y=- x+1 through (4,4). y= - x+ 8