Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
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Exercise 15 Page 357

Practice makes perfect
a

We bought supplies before we groomed any pets, so we are starting off $30 in debt. Let's think about this in terms of the number of pets groomed x and our total profit y. When we have groomed 0 pets, our total profit is -$30.

Groomed pets: & x=0 Profit is-$30: & y=-30 Because this relation has an x-value of 0, we know that this is going to be the y-intercept of our equation. If we want to write the equation in slope-intercept form, the y-value of the relation is the value of b. b= -30 We plan on charging $ 5 for each groomed pet, so we can write an expression for the profits. 5x In this expression 5 can be considered the slope m of our equation. y= mx+ b ⇒ y= 5x - 30

b

To graph our equation we should plot our y-intercept and use our slope to find a second point.

We can then draw a line through those points to show our function.

We already found the y-intercept to be -30 in Part A. Using our graph, we can see that the x-intercept is 6. This means that after the 6^\text{th} groomed pet we will finally break even from our purchase of supplies and we will start making a profit.