Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
1. Inequalities and Their Graphs
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Exercise 60 Page 170

Think for which value will the inequality become an equality. Then, analyze nearby values to see what happens.

D

Practice makes perfect
We need to find the correct graph for the given inequality. -3 < - x

The right-hand side of the inequality uses - x. This means that it is involving the opposites of the values for x shown in the graphs. Notice that the inequality would become an equality when x = 3, since then - x =- 3. Let's then analyze some values near 3 to see when the inequality holds.

x - x -3 ? < - x
1 -1 âś“
2 -2 âś“
3 -3 *
4 -4 *
5 -5 *

We can see that the inequality only holds for values of x that are less than 3. The graph which shades all numbers less than 3 is option D.

Alternative Solution

Manipulating the inequality

It would be easier to have an inequality in terms of x instead of - x. We can work with inequalities similarly as we do with equations, but there is an important difference. Think of the statement 5 > - 10. This is a true statement since 5 is greater than -10. If we add the same quantity to both sides or multiply by any positive number the statement will still be true.

5 + 3 > 10 +3 ⇒ 8 > -7 3(5) > 3(- 10) ⇒ 15 > - 30 Let's now try multiplying by a negative number. -3(5) ? > -3(-10) ⇒ - 15 < 30. Did you see what happened? When we multiplied by a negative number both sides, what was negative became positive, and what was positive became negative. What was larger became smaller, and what was smaller became larger. Everything reversed. Hence, when we multiply by a negative number we must reverse the inequality sign. With this in mind, we can rewrite the exercise's inequality .
-3 < - x
3 > x
x < 3
We can see that we arrived to the same conclusion. The solutions will be all values that are less that 3. This is represented by graph D.