Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
1. Inequalities and Their Graphs
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Exercise 13 Page 168

Practice makes perfect
a By substituting m=2 into the inequality, we can check whether the inequality holds true.
8m -6 ≤ 10
8( 2) -6 ? ≤ 10
16 -6 ? ≤ 10
10≤10 ✓
Since 10 is equal to 10, the inequality is true. This means that m=2 is a solution to the inequality.
b Let's do the same thing again and substitute m=3 into the inequality.
8m -6 ≤ 10
8( 3) -6 ? ≤ 10
24 -6 ? ≤ 10
18≰ 10 *
We know that 18 is not less than or equal to 10. Therefore, m=3 is not a solution to the inequality.
c Let's substitute m=-1 into the inequality and check its validity.
8m -6 ≤ 10
8( -1) -6 ? ≤ 10
-8 -6 ? ≤ 10
-14≤10 ✓
A negative number is always less than a positive number. Hence, the inequality is true. This means that m=-1 is a solution.