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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

Exercise 4 Page 229

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

F

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we will first subtract 3w from both sides of the equation to get rid of the variable from the right-hand side.

w-4=18+3w

LHS-3w=RHS-3w

w-4-3w=18+3w-3w

Subtract terms

- 2w-4=18

LHS+4=RHS+4

- 2w-4+4=18+4

Add terms

- 2w=22

.LHS /(- 2).=.RHS /(- 2).

- 2w/- 2=22/- 2

▼

Calculate quotient

MovePartNumRight

a* b/c=a/c* b

- 2/- 2w=22/- 2

a/a=1

w=22/- 2

MoveNegDenomToFrac

Put minus sign in front of fraction

w=-22/2

Calculate quotient

w=- 11

Therefore, w=- 11 is the solution to the equation. It corresponds to option F.