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Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

Finish the assignment

Exercise 19 Page 230

You can solve for the variable by using the Cross Product Property.

x≈ 6.429

Practice makes perfect

To solve the proportion, we will start by using the Cross Product Property.

7/5=9/x

Cross multiply

7(x)=5(9)

Multiply

7x=45

.LHS /7.=.RHS /7.

7x/7=45/7

Calculate quotient

x=6.428571...

Round to 3 decimal place(s)

x≈ 6.429

The above tells us that x is approximately 6.429.