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Pearson Algebra 1 Common Core, 2011 View details

Cumulative Standards Review

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Exercise 31 Page 230

Use Properties of Equality to isolate h on one side of the equation.

h=3V/π r^2

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To solve the given formula for h, we will use the Properties of Equality to apply inverse operations on the equation. Remember, only like terms can be combined.

V=1/3π r^2 h

MultEqn

LHS * 3=RHS* 3

3V=π r^2 h

DivEqn

.LHS /π.=.RHS /π.

3V/π=r^2 h

DivEqn

.LHS /r^2.=.RHS /r^2.

3V/π r^2=h

RearrangeEqn

Rearrange equation

h=3V/π r^2

Note that in this case, we were asked to solve for the height h, given the formula for the volume of a cone. A solution of h= 3Vπ r^2 means that we have solved for the height of the given cone.

Exercise 31 Page 230

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