Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
2. Frequency and Histograms
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Exercise 36 Page 737

To factor a trinomial, think of the process as multiplying two binomials in reverse.

C

Practice makes perfect
To factor a trinomial with a leading coefficient of 1, think of the process as multiplying two binomials in reverse. Let's start by taking a look at the constant term. x^2-6x - 16 In this case, we have - 16. This is a negative number, so for the product of the constant terms in the factors to be negative, these constants must have the opposite sign (one positive and one negative.)
Factor Constants Product of Constants
- 1 and 16 - 16
1 and - 16 - 16
- 2 and 8 - 16
2 and -8 - 16
- 4 and 4 - 16

Next, let's consider the coefficient of the linear term. x^2 -6x -16 For this term, we need the sum of the factors that produced the constant term to equal the coefficient of the linear term, -6.

Factors Sum of Factors
- 1 and 16 15
1 and - 16 - 15
- 2 and 8 6
2 and -8 -6
- 4 and 4 0
We found the factors whose product is - 16 and whose sum is -6. x^2 -6x -16 ⇔ (x+2)(x-8) This result corresponds to answer C.

Checking Our Answer

Check your answer âś“
We can check our answer by applying the Distributive Property and comparing the result with the given expression.
(x + 2) (x - 8)
x(x - 8) + 2 (x - 8)
x^2 - 8 x + 2 (x - 8)
x^2 - 8 x + 2 x - 16
x^2 - 6 x - 16
After applying the Distributive Property and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!