Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. The Distributive Property
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Exercise 8 Page 49

Practice makes perfect
a To add variables they have to be like terms. Consider the given expression.

4xy^3+5x^3y Notice the location of the exponent in each term. For the first term, the y factor is being raised, but in the second term the x factor is being raised. 4x y^3+5 x^3y Therefore, the terms are not like and we cannot add them. This means that our expression is already fully simplified.

b Observing the given expression, we can see that there is a term outside the parentheses that can be distributed.
- (y-1) ⇔ - 1(y-1) Let's distribute -1.
- 1(y-1)
y(- 1)-1(- 1)
y(- 1)+1 * 1
- y * 1+1 * 1
- y+1
The given expression was not simplified, because there was a term that could be distributed. The fully simplified expression in this case should be - y+1.
c Let's look at the given expression to see if there are any like terms that could be added.
5x^2+12xy-3yxThe first term has an x^2 and the second has an x0,y so these cannot be added together. However, xy and yx can be added together thanks to the Commutative Property of Multiplication.
12xy-3yx
12xy-3 xy
9xy
We can now write the fully simplified expression. 5x^2+9xy Therefore, the given expression was not simplified.