Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
7. The Distributive Property
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Exercise 67 Page 50

To simplify, distribute 13 to the terms inside the parentheses.

Phrase: one-third of the difference of 6 times x and 1
Simplified expression: 2x-1/3

Practice makes perfect

We will start by writing a phrase for the expression, then simplify it.

Phrase

Let's start from the left. We have a factor 13, which is multiplied by the expression inside the parentheses. Let's write this. one-third of...

Now we will look at what is inside the parentheses. We see that there is a subtraction sign, which means we have a difference of two terms. These two terms are 6x and 1. ... the difference of 6x and 1 Also, we can rewrite 6x. ... 6 times x ... Now we can write the final phrase. 1/3 & ( 6x-1) one-third of & the difference of 6 times x and 1

Simplifying

To simplify the expression, we have to distribute the 13.
1/3(6x-1)
1/3 ( 6x ) + 1/3 ( - 1 )
1/3 ( 6x ) - 1/3 ( 1 )
6x/3-1/3
2x-1/3
The expression simplifies to 2x- 13.