Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
4. Properties of Real Numbers
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Exercise 63 Page 28

Rewrite the numbers to be in decimal form.

-17, 1.4, 8/5, 10^2

Practice makes perfect
Consider the given set of numbers. {8/5,1.4,-17,10^2} In order to compare them, we will rewrite them all to be in decimal form. The numbers -17 and 1.4 are already in decimal form, so we do not need to change these numbers at all. Let's start by calculating 10^2. 10^2=100 Now, we can calculate 85 by rewriting this fraction.
8/5
8*2/5*2
16/10
1.6
Finally, let's compare them. We can see that ordering from the least to the greatest gives us: {-17,1.4,1.6,100} ⇓ {-17, 1.4, 8/5, 10^2 }

Alternative Solution

A different way of thinking...
We could have arrived to the same conclusion if we think about the given numbers for a little while. First of all, -17 is the only negative number, so it must be the least. Then, to decide which is greater, 1.4 or 85, we can rewrite 1.4 as a fraction.
1.4
â–Ľ
Rewrite as fraction
1.4 * 10/10
14/10
7/5
Since 1.4= 75 we know that 1.4= 75 < 85 We also know that any real number greater than 1 will increase rapidly when raised to a positive integer power. Thia means that, 10^2 must be our greatest number. Therefore, the ordering once again gives us: {-17, 1.4, 8/5, 10^2 }