McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
2. Medians and Altitudes of Triangles
Continue to next subchapter

Exercise 38 Page 424

Draw three altitudes in a right triangle and locate their point of intersection.

True, see solution.

Practice makes perfect
Let's start with recalling that an orthocenter of a triangle is a point of intersection of the triangle altitudes. We will draw three altitudes in a right triangle and locate its orthocenter. Let's review that an altitude of a triangle is a segment from a vertex to the line containing the opposite side and perpendicular to the line containing that side.

As we can see, since ∠ ACB is a right angle, side BC is perpendicular to AC and side AC is perpendicular to BC. Thus, these are the altitudes of △ ABC. The third altitude is CD. All the altitudes intersect at point C, which is a vertex of △ ABC.

Generally speaking, two sides of a right triangle that form a right angle are also the altitudes of a triangle and they intersect at a triangle vertex. The last altitude is going out from that vertex (as it's shown above). Therefore, the altitudes of a right triangle always intersect at its vertex. The statement is true.