McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
2. Medians and Altitudes of Triangles
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Exercise 39 Page 424

Write the equations for two medians in slope-intercept form and solve the system of equations.

(1, 53), see solution.

Practice makes perfect

We are given the coordinates of the triangle vertices A, B, and C. Let's plot these points on a coordinate plane and draw the triangle â–ł ABC.

Now, we can recall that a centroid of a triangle is a point of intersection of the triangle medians. Let's draw two medians and find their point of intersection.

First Median

In order to draw a median of a triangle, we need to choose a vertex and find a midpoint of the opposite to it side. Let's choose A. We can find the midpoint of BC by substituting the coordinates of B and C into the Midpoint Formula.
(x_1+x_2/2,y_1+y_2/2)
â–Ľ
Substitute coordinates and evaluate
(2+ 4/2,5+( - 3)/2)
(2+4/2,5-3/2)
(6/2,2/2)
(3,1)
Now let's plot the midpoint of BC, which we can name N, and draw the median AN.
Let's now find the equation of AN. We will use the slope-intecept form. From the diagram, we can see that AN intersects the y-axis at 2, so the y-intercept of the line is 2. b=2 To calculate the slope of AN, we can substitute the coordinates of A and N into the Slope Formula.
m=y_2-y_1/x_2-x_1
â–Ľ
Substitute coordinates and evaluate
m=1- 3/3-( - 3)
m=1-3/3+3
m=- 2/6
m=- 2/6
m=- 1/3
Now that we know both the slope and y-intercept of AN, we can write its equation in slope-intercept form. y= mx+ b ⇒ y= - 13x+ 2

Second Median

Similarly, we can draw the second median from the vertex B. We can find the midpoint of the opposite side AC by substituting the coordinates of A and C into the Midpoint Formula.
(x_1+x_2/2,y_1+y_2/2)
â–Ľ
Substitute coordinates and evaluate
(- 3+ 4/2,3+( - 3)/2)
(- 3+4/2,3-3/2)
(1/2,0/2)
(1/2,0)
Let's now plot the midpoint of AC, name it M, and draw the median BM.
We need to find the equation of BM in slope-intercept form. First, we can calculate the slope by substituting the coordinates of B and M into the Slope Formula.
m=y_2-y_1/x_2-x_1
â–Ľ
Substitute coordinates and evaluate
m=0- 5/12- 2
m=0-5/12- 42
m=- 5/- 32
m=5/32
m=10/3
So far the equation is the following. y= mx+b ⇒ y= 10/3x+b To find the y-intercept b, we will substitute point B(2,5) into the above equation and solve it for b.
y=10/3x+b
â–Ľ
Substitute coordinates and evaluate
5=10/3( 2)+b
5=20/3+b
5-20/3=b
15/3-20/3=b
- 5/3=b
b=- 5/3
The equation of BM in slope-intercept form is as follows. y=10/3x+ b ⇒ y=10/3x+( - 5/3)

Find Centroid

We have found two equations of the medians of â–ł ABC. Using them, we can form a system of equations. y=- 13x+2 y= 103x+(- 53) If we solve it we will find the common solution for both equations. It is a point of intersection of these medians and the centroid that we were asked to find. Let's use the Substitution Method.
y=- 13x+2 & (I) y= 103x+(- 53) & (II)
y=- 13x+2 y= 103x- 53
â–Ľ
Solve by substitution
103x- 53=- 13x+2 y= 103x- 53
113x- 53=2 y= 103x- 53
113x=2+ 53 y= 103x- 53
113x= 63+ 53 y= 103x- 53
113x= 113 y= 103x- 53
x=1 y= 103x- 53
x=1 y= 103( 1)- 53
x=1 y= 103- 53
x=1 y= 53
The coordinates of the centroid of â–ł ABC are (1, 53).