McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Study Guide and Review
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Exercise 19 Page 325

Statements
Reasons
1.
AB=DC
1.
Given
2.
AB+BC=DC+BC
2.
Addition Property of Equality
3.
AB+BC=DC+CB
3.
Properties of Line Segment
4.
AC=DB
4.
Segment Addition Postulate
Practice makes perfect

Let's start with examining the given statement, the statement that we want to prove and the figure.

Given: AB=DC Prove: AC=DB We will write a two-column proof. In our first step, we will state the given statement.

Given AB=DC Next, we will use the Addition Property of Equality to add BC to both sides of the equation. Addition Property of Equality AB+ BC=DC+ BC Knowing that the length from B to C is equal to the length from C to B, we can rewrite BC as CB. Properties of Line Segments AB+BC=DC+CB Finally, we will add the terms by the Segment Addition Postulate to complete our proof. Segment Addition Postulate AC=DB Combining these steps, let's form our two-column proof.

Statements
Reasons
1.
AB=DC
1.
Given
2.
AB+BC=DC+BC
2.
Addition Property of Equality
3.
AB+BC=DC+CB
3.
Properties of Line Segments
4.
AC=DB
4.
Segment Addition Postulate