McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Study Guide and Review
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Exercise 36 Page 266

Substitute the values into the given formula. Then, use a calculator to find the approximate result.

≈ 251ft/s

Practice makes perfect
We can find the velocity of a dropped object when it hits the ground using the given formula. v = sqrt(2gd) In this formula, g is the acceleration due to gravity and d is the distance in feet that the object drops. We are given that a penny is dropped from 984feet and that the gravitational acceleration is 32 feet per second squared (ft/s^2). Let's substitute d = 984 and g= 32 into the formula to find the speed of the penny.
v = sqrt(2gd)
v = sqrt(2( 32)( 984))
Simplify right-hand side
v = sqrt(62 976)
v = 250.950194...
v ≈ 251
Therefore, the speed of the penny is about 251 feet per second (ft/s).