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Rearrange the radical equation so that the radical expression is isolated. Then raise both sides of the equation to the second power.
-41
We will find and check the solution of the given equation.
To solve an equation with a variable expression inside a radical, we will first rearrange the radical equation so that the radical expression is isolated. Then, we can raise both sides of the equation to a power equal to the index of the radical. In this case, we will raise both sides of the equation to the second power. Let's do it!
LHS+6=RHS+6
LHS^2=RHS^2
( sqrt(a) )^2 = a
Calculate power
LHS-5=RHS-5
.LHS /(-4).=.RHS /(-4).
The solution of our equation is x= -41. Now, let's check whether our solution is extraneous.
To check our solution, we will substitute -41 for x into the original equation. If we obtain a true statement, the solution is not extraneous. Otherwise, the solution is extraneous.
x= -41
- a(- b)=a* b
Multiply
Add terms
Calculate root
Subtract term
We obtained a true statement, so x=-41 is a solution to the equation.