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Rearrange the radical equation so that the radical expression is isolated. Then raise both sides of the equation to the second power.
No solution.
We will find and check the solution of the given equation.
To solve an equation with a variable expression inside a radical, we will first rearrange the radical equation so that the radical expression is isolated. Then, we can raise both sides of the equation to a power equal to the index of the radical. In this case, we will raise both sides of the equation to the second power. Let's do it!
LHS-10=RHS-10
.LHS /2.=.RHS /2.
LHS^2=RHS^2
( sqrt(a) )^2 = a
Calculate power
The solution of our equation is x= 25. Now, let's check whether our solution is extraneous.
To check our solution, we will substitute 25 for x into the original equation. If we obtain a true statement, the solution is not extraneous. Otherwise, the solution is extraneous.
We obtained a false statement, so x=25 is not a solution to the equation.