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32
We will find and check the solution of the given equation.
To solve equations with a variable expression inside a radical, we first want to make sure the radical is isolated. Then, we can raise both sides of the equation to a power equal to the index of the radical. In this case, we will raise both sides of the equation to the second power. Let's do it!
LHS^2=RHS^2
( sqrt(a) )^2 = a
Calculate power
LHS-4=RHS-4
The solution of our equation is a= 32. Now, let's check whether our solution is extraneous.
To check our solution, we will substitute 32 for a into the original equation. If we obtain a true statement, the solution is not extraneous. Otherwise, the solution is extraneous.
a= 32
Add terms
Calculate root
We obtained a true statement, so a=32 is a solution to the equation.