McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
Mid-Chapter Quiz
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Exercise 15 Page 749

Notice that the diameter of a circle is also the diagonal of a square.

14sqrt(2) or approximately 19.8 inches

We are given that a square with sides of 14 inches is inscribed in a circle. We want to find the diameter of the circle. Let's sketch a diagram of this situation.

As we can see, the diameter of the circle is also a diagonal of the square. We can call it d. Notice that because a square has four right angles, two sides of a square and the diagonal form a right triangle.
Now we can write an equation using the Pythagorean Theorem. According to this theorem the sum of the squared legs of a right triangle is equal to its squared hypotenuse. d^2= 14^2+ 14^2 Let's solve the above equation. Notice that since d represents a dimension we will consider only the positive case when taking the square root of d^2.
d^2=14^2+14^2
Solve for d
d^2=196+196
d^2=392
sqrt(d^2)=sqrt(392)
d=sqrt(392)
d=sqrt(196*2)
d=sqrt(196)*sqrt(2)
d=14*sqrt(2)
d=14sqrt(2)
d=19.7989...
d≈ 19.8
The diameter of the circle is approximately 19.8 inches.