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| Student Learning Objectives: |
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| | 11 Theory slides |
| | 7 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Try your knowledge on these topics.
In the diagram below, can the larger circle be mapped onto the smaller circle? What transformations are involved?
Consider two concentric circles with common center O and radii 4 and 6.
Let A and B be two points on the smaller and larger circles, respectively, collinear with O. Also, consider the ray through A and B, with endpoint O.
Since 4* 32= 6, point B is the image of point A after a dilation with center O and scale factor 32. Likewise, if any point on the smaller circle is dilated through O by a factor of 32, its image will fall on the larger circle. Hence, the circles are related by a dilation, and so, are similar. The same argument can be used for any two concentric circles. This leads to the following conclusion.
Concentric circles are similar.
Dilate the concentric circles below so that they map onto each other.
Given two concentric circles on a coordinate plane, Zosia is trying to determine the transformation that maps the smaller circle onto the larger circle.
So far, Zosia is considering four different options. Help Zosia make up her mind!
Therefore, to map the smaller circle onto the larger circle, a dilation must be performed. Furthermore, since the radius of the larger circle is twice the radius of the smaller circle, the scale factor of the dilation must be 2. Finally, since the circles are concentric, the center of dilation is the center of the circles, which is the point (2,- 1).
Now, given a different pair of concentric circles, Zosia wants to find the transformation that maps the larger circle onto the smaller circle.
Again, Zosia is considering four different options. Help Zosia make up her mind!
Therefore, to map the larger circle onto the smaller circle, a dilation must be performed. Furthermore, since the radius of the smaller circle is one third the radius of the larger circle, the scale factor of the dilation must be 13. Finally, since the circles are concentric, the center of dilation is the center of the circles, which is the point (4,1).
Now, consider two circles with different centers. One of the circles can be translated so that they become concentric circles.
Non-concentric circles are similar.
With this information and knowing that any two concentric circles are also similar, a more general statement can be made.
All circles are similar.
Two non-concentric circles can be mapped onto each other through either a translation or by a combination of a translation and a dilation. Therefore, non-concentric circles are similar. Translate and dilate the non-concentric circles below so that they map onto each other.
Diego has been asked to identify the transformation that maps the circle on the left onto the circle on the right.
Diego is considering the four different options that are shown below. Which is the correct choice?
Therefore, to map the circle on the left onto the circle on the right, translation is the only transformation that must be performed. The circle on the left must be translated 9 units to the right and 4 units up.
Finally, Diego wants to identify the combination of transformations that maps the smaller circle onto the larger circle.
Diego is considering four different options. Help Diego make up his mind for the last time!
Therefore, to map the smaller circle onto the larger circle, a translation and a dilation must be combined. The translation must be performed 8.5 units to the right and 4.5 units up. Then, since 3* 1.5 is equal to 4.5, the scale factor of the dilation must be 1.5.
In this lesson, it has been proven that all circles are similar by using similarity transformations. Therefore, any theorem that is valid for one circle, is also valid for all circles. This can be exemplified by the following theorem.
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If two inscribed angles of a circle intercept the same arc, then they are congruent. |
The diagram visualizes the theorem.
The scale factor from ⊙ A to ⊙ B is 13. What is the circumference C_B if C_A is 12 cm?
We know that the scale factor from ⊙ A to ⊙ B is 13. Let's recall that in similar figures the ratio of corresponding lengths equals the scale factor. This is true for the circumference of circles as well. Therefore, we can write the following equation. C_B/C_A= 1/3 ⇔ C_B=1/3C_A If we substitute 12 for C_A, we can find the circumference of B.
The circumference of ⊙ B is 4 cm.
Ramsha is installing a circular fountain in her backyard. In addition to the fountain, Ramsha will lay grass around the fountain.
What is the scale factor if we were to dilate the fountain's base to match the circle created by the grass? Ramsha wants the circle of grass to have a radius of 10 feet.
We know that the radius of the grass circle is 10 feet. Notice that the radius of the grass is the sum of the lengths we see in the diagram.
With this information, we can write and solve an equation containing r. r+r+2=10 ⇔ r=4 As we can see, the radius of the fountain is 4 feet. Now that we know the radius of both circles, we can determine the scale factor between them. r_G/r_F=10/4=5/2
Concentric circles are circles with a common center but different radii. When we look at the diagram, we can see that i and ii have a common center but different radius which means we have found one set of concentric circles.
However, we can also see a second set of concentric circles in the diagram. Both iii. and iv. have a common center and different radii as well.
This means we have two sets of concentric circles.
According to the Similar Circles Theorem, all of the drawn circles are similar to i.