McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
7. Vectors
Continue to next subchapter

Exercise 55 Page 690

Determine the trigonometric ratio to use according to the given information and the unknown.

B

Practice makes perfect

We are given the length of one leg and a hypotenuse of a right triangle, and want to find the measure of one of its acute angles.

Note that we are given the opposite side to the unknown angle and the hypotenuse. Therefore, to find its measure we will use the sine ratio. sin A = Length of leg opposite to∠ A/Length of hypotenuse In our triangle, we have that the length of the leg opposite to ∠ A and the hypotenuse are 22 and 35.
sin A = opposite/hypotenuse
sin A = 22/35
The sine of the angle is 2235. Now, to isolate m∠ A we will use the inverse function of sin. sin A=22/35 ⇔ m∠ A=sin ^(- 1)22/35 Let's use a calculator to find the value of sin ^(- 1) 2235. First, we will set our calculator into degree mode. To do so, push MODE, select Degree instead of Radian in the third row, and push ENTER. Next, we push 2ND followed by SIN, introduce the value 2235, and press ENTER.

The angle is about 38.9^(∘), which corresponds to option B.