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McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

2. The Pythagorean Theorem and Its Converse

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Exercise 70 Page 637

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

2 sqrt(3)

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we need to start by using the Division Property of Equality to isolate the variable term.

18=3x sqrt(3)

.LHS /3.=.RHS /3.

6=x sqrt(3)

.LHS /sqrt(3).=.RHS /sqrt(3).

6/sqrt(3)=x

a/b=a * sqrt(3)/b * sqrt(3)

6 * sqrt(3)/sqrt(3)* sqrt(3)=x

Multiply

6 sqrt(3)/(sqrt(3))^2=x

( sqrt(a) )^2 = a

6 sqrt(3)/3=x

a/b=.a /3./.b /3.

2 sqrt(3) = x

Rearrange equation

x = 2 sqrt(3)

The solution to the equation is x=2 sqrt(3).

Subchapter links

Exercises p.633-637