McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
Study Guide and Review
Continue to next subchapter

Exercise 35 Page 705

Sketch a diagram describing the given situation. Then recall the definition of tangent.

≈ 86.6 feet

Practice makes perfect

We are given that Jen wants to know the height of a cell-phone tower, which we will call h. We also know that she walked 50 feet from the tower, and the angle of elevation from her position to the top of the tower is 60^(∘). Let's sketch a diagram describing the given situation.

To find the value of h, we can use one of the trigonometric ratios. Let's recall that the tangent of ∠ A is the ratio of the leg opposite ∠ A to the leg adjacent ∠ A. Using this definition, we can create an equation for tan 60^(∘). tan 60^(∘)=h/50 Let's solve the above equation.
tan 60^(∘)=h/50
50tan60^(∘)=h
h=50tan60^(∘)
h=86.6025...
h≈ 86.6
The height of the cell-phone tower is approximately 86.6 feet.