McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
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Exercise 24 Page 704

Sketch a diagram describing the given situation, and then recall the 30^(∘)-60^(∘)-90^(∘) Triangle Theorem.

10 ft

Practice makes perfect

We are given that Jason is adding a climbing wall to his little brother's swing-set, and we know that he starts building 5 feet out from the existing structure and that he wants it to have an angle of 60^(∘). Let's sketch a diagram describing the given situation.

Since we are asked to determine the length of the wall, let l represent this length.

Now let's recall the 30^(∘)-60^(∘)-90^(∘) Triangle Theorem. This theorem tells us that the length of the hypotenuse of this right triangle is 2 times the length of the shorter leg s and that the length of the longer leg is sqrt(3) times the length of the shorter leg.

According to this theorem, the value of l is two times the distance between Jason and the existing structure, 5. l=2( 5)=10 The length of the wall is 10 feet.