body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Integrated II, 2012

MH

McGraw Hill Integrated II, 2012 View details

Study Guide and Review

Continue to next subchapter

Exercise 16 Page 703

Use the Pythagorean Theorem.

2sqrt(221)≈ 29.7

Practice makes perfect

To find the missing side of the triangle, we will use the Pythagorean Theorem. a^2+b^2=c^2

In the formula, a and b are the legs and c is the hypotenuse of a right triangle. We are given a triangle with a=20, b=22, and c=x.

Let's substitute these values into the formula and solve for x.

a^2+b^2=c^2

SubstituteValues

Substitute values

20^2+ 22^2= x^2

▼

Solve for x

Calculate power

400+484=x^2

Add terms

884=x^2

sqrt(LHS)=sqrt(RHS)

sqrt(884)=x

Rearrange equation

x=sqrt(884)

SplitIntoFactors

Split into factors

x=sqrt(4 * 221)

sqrt(a* b)=sqrt(a)*sqrt(b)

x=sqrt(4)*sqrt(221)

Calculate root

x=2sqrt(221)

Use a calculator

x=29.73213...

Round to 1 decimal place(s)

x≈ 29.7

Since a negative side length does not make sense, we only need to consider positive solutions.

Subchapter links

1 Geometric Mean p.703

2 The Pythagorean Theorem and Its Converse p.703

3 Special Right Triangles p.704

4 Trigonometry p.704

5 Angles of Elevation and Depression p.705

6 The Law of Sines and Law of Cosines p.705

7 Vectors p.706

8 Dilations p.706