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Look for a common angle to both triangles. Use the Segment Addition Postulate to show that the corresponding sides that include the common angle are proportional. Also, use the Side-Angle-Side (SAS) Similarity Theorem to obtain the desired results.
Statements
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Reasons
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1. △ FGH, J and K are midpoints of FH and HG respectively
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1. Given
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2. FH = FJ+JH and GH = GK+KH
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2. Segment Addition Postulate
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3. FJ = JH and GK = KH
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3. Definition of congruent segments
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4. FH = 2HJ and GH = 2HK
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4. Substitution
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5. FH/HJ = 2 and GH/HK = 2
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5. Division Property of Equality
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6. FH/HJ = GH/HK
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6. Transitive Property of Equality
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7. ∠ H ≅ ∠ H
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7. Reflexive Property of Congruence
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8. △ FGH ~ △ JKH
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8. SAS Similarity Theorem
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9. ∠ F ≅ ∠ HJK
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9. Definition of similar triangles
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10. JK∥FG
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10. Corresponding Angles Converse
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11. FG/JK = GH/KH
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11. Definition of similar triangles
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12. FG/JK = 2
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12. Substitution
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13. JK=1/2FG
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13. Simplifying
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Let's consider △ FGH and let J and K be the midpoints of FH and GH, respectively.
FH = 2HJ GH = 2HK ⇒ FH/HJ = 2 [0.25cm] GH/HK = 2 Because both proportions equal the same number 2, we can use the Transitive Property of Equality to obtain the following equation. FH/HJ = GH/HK Additionally, notice that ∠ H is common to both △ FGH and △ JKH. The Reflexive Property of Congruence gives us ∠ H ≅ ∠ H. FH/HJ = GH/HK and ∠ H ≅ ∠ H In consequence, the Side-Angle-Side (SAS) Similarity Theorem tells us that △ FGH ~ △ JKH. Therefore, the corresponding angles are congruent.
Given: & △ FGH, J andK are midpoints of & FHandHG respectively Prove: & JK∥FGandJK = 12FG Let's summarize the proof we did above in the following two-column table.
Statements
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Reasons
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1. △ FGH, J and K are midpoints of FH and HG respectively
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1. Given
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2. FH = FJ+JH and GH = GK+KH
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2. Segment Addition Postulate
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3. FJ = JH and GK = KH
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3. Definition of congruent segments
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4. FH = 2HJ and GH = 2HK
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4. Substitution
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5. FH/HJ = 2 and GH/HK = 2
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5. Division Property of Equality
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6. FH/HJ = GH/HK
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6. Transitive Property of Equality
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7. ∠ H ≅ ∠ H
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7. Reflexive Property of Congruence
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8. △ FGH ~ △ JKH
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8. SAS Similarity Theorem
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9. ∠ F ≅ ∠ HJK
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9. Definition of similar triangles
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10. JK∥FG
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10. Corresponding Angles Converse
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11. FG/JK = GH/KH
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11. Definition of similar triangles
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12. FG/JK = 2
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12. Substitution
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13. JK=1/2FG
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13. Simplifying
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