McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
4. Parallel Lines and Proportional Parts
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Exercise 58 Page 499

Review the Triangle Similarity Theorems that can help you prove that two triangles are similar.

Similar Triangles: △ SWR ~ △ RWT
Measures: RT=15 and RS=20

Practice makes perfect

To prove that two triangles are similar we will use one of the Triangle Similarity Theorems. Then we will find the desired measures.

Similar Triangles

We want to identify the similar triangles in the given diagram.

Let's recall the Side-Angle-Side Similarity Theorem.

If the lengths of two sides of one triangle are proportional to the lengths of two corresponding sides of another triangle and the included angles are congruent, then the triangles are similar.

Notice that ∠ SWR and ∠ RWT form a linear pair. Thus, they are supplementary angles. Since ∠ RWT is a right angle so is ∠ SWR, and hence they are congruent. Let's check whether the corresponding sides that include ∠ SWR and ∠ RWT are proportional. cccc SW/WR & = & 16/12 & = & 4/3 [0.8em] WR/WT & = & 12/9 & = & 4/3 As we can see, with the ratios being equal this means that the corresponding sides are proportional. According to the Side-Angle-Side Similarity Theorem, the given triangles are similar. △ SWR ~ △ RWT

Finding the Measures

Using our similarity statement from above, we can identify two pairs of corresponding sides that will help us find the requested lengths. RS corresponds with RT SW corresponds with WR Recall that corresponding segments of similar figures will have proportional lengths. We are given expressions for the lengths of these sides which we can use to write a proportion. RS/RT = SW/WR ⇕ 6x+2/4x+3 = 16/12 Let's solve this equation to find x.
6x+2/4x+3 = 16/12
Solve for x
6x+2=16/12(4x+3)
6x+2=4/3(4x+3)
3(6x+2)=4(4x+3)
18x+6=4(4x+3)
18x+6=16x+12
2x+6=12
2x=6
x=3
Now that we know the value of x, we can find RT and RS. We will substitute x= 3 into the expressions for the lengths.
Measure Expression x=3 Simplified
RT 4x+3 4( 3)+3 15
RS 6x+2 6( 3)+2 20

We found that RT=15 and RS=20.