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The equation of a vertical hyperbola is a2(y−k)2−b2(x−h)2=1. The vertices are (h,k±a). How can you find the foci and the asymptotes?
Vertices: (4,3) and (4,-5)
Foci: (4,4) and (4,-6)
Asymptotes: y=±34(x−4)−1
Graph:
We will find the desired information, and use it to draw the graph of the hyperbola.
Vertical Hyperbola with Center (h,k) | |
---|---|
Equation | a2(y−k)2−b2(x−h)2=1 |
Transverse axis | Vertical |
Vertices | (h,k±a) |
Foci | (h,k±c), where c2=a2+b2 |
Asymptotes | y−k=±ba(x−h) |
To graph the function, let's summarize all of the information that we have found.
Equation | 42(y−(-1))2−32(x−4)2=1 |
Transverse axis | Vertical |
Vertices | (4,3) and (4,-5) |
Foci | (4,4) and (4,-6) |
Asymptotes | y=±34(x−4)−1 |
Finally, we can graph our hyperbola with center (4,-1).