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McGraw Hill Glencoe Algebra 1, 2012

MH

McGraw Hill Glencoe Algebra 1, 2012 View details

7. Inverse Linear Functions

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Exercise 62 Page 270

Use the Properties of Equality to isolate the variable.

-1/3

Practice makes perfect

To solve the equation, we have to isolate t on one side by performing inverse operations. Using the Multiplication Property of Equality, we will multiply both sides of the equation by t.

9/t=-27

LHS * t=RHS* t

9/t* t=- 27* t

FracMultDenomToNumber

a/t* t = a

9=- 27* t

Now, we will use the Division Property of Equality to isolate t.

9=- 27* t

.LHS /(- 27).=.RHS /(- 27).

9/-27=- 27* t/-27

MoveNegDenomToFrac

Put minus sign in front of fraction

-9/27=- 27* t/- 27

a/b=.a /9./.b /9.

-1/3=- 27* t/- 27

MovePartNumRight

a* b/c=a/c* b

-1/3=- 27/- 27 * t

- a/- b=a/b

-1/3=27/27 * t

a/a=1

-1/3=1 * t

Identity Property of Multiplication

-1/3=t

Rearrange equation

t=-1/3

Therefore, t=- 13 is the solution to the equation.

Subchapter links

Check Your Understanding p.267

Practice and Problem Solving p.267-269

H.O.T. Problems p.269

Standardized Test Practice p.270

Spiral Review p.270

Skills Review p.270