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$f(x)=ax_{2}+bx+c $ This kind of equation can give us a lot of information about the parabola by observing the values of $a,$ $b,$ and $c.$ $f(x)=3x_{2}+2x⇔f(x)=3x_{2}+2x+0 $ We see that for the given equation $a=3,$ $b=2,$ and $c=0.$ These values will give us information about the parabola. Consider the point at which the curve of the parabola changes direction.

This point is the vertex of the parabola, and defines the axis of symmetry. If we want to calculate the $x-$value of this point, we can substitute the given values of $a$ and $b$ into the expression $-2ab $ and simplify. Remember that the axis of symmetry is the vertical line that passes through the vertex, dividing a parabola into two mirror images. Since every point on this line will have the same $x-$coordinate as the vertex, we can form its equation. $x=-31 $ b

$f(x)=3x_{2}+2x$

Substitute$x=-31 $

$f(31 )=3(-31 )_{2}+2(-31 )$

Simplify right-hand side

NegBaseToPosPow$(-a)_{2}=a_{2}$

$f(31 )=3(31 )_{2}+2(-31 )$

PowQuot$(ba )_{m}=b_{m}a_{m} $

$f(31 )=3(91 )+2(-31 )$

MultPosNeg$a(-b)=-a⋅b$

$f(31 )=3(91 )−2(31 )$

MoveLeftFacToNum$a⋅cb =ca⋅b $

$f(31 )=93 −32 $

ReduceFrac$ba =b/3a/3 $

$f(31 )=31 −32 $

SubFracSubtract fractions

$f(31 )=-31 $

One common mistake when identifying the key features of a parabola algebraically is forgetting to include the negatives in the values of these constants. The standard form is addition only, so any subtraction must be treated as negative values of $a,$ $b,$ or $c.$ Let's look at an example. $y=ax_{2}+bx+cy=-9x_{2}−18x−1⇔y=-9x_{2}+(-18x)+(-1) $ In this case, the values of $a,$ $b,$ and $c$ are $-9,$ $-18,$ and $-1.$ They are NOT $-9,$ $18,$ and $1.$ $a=-9,b=18,c=1×a=-9,b=-18,c=-1✓ $