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To find the balance we will use the compound interest formula. In this formula, $y$ is the amount in the account after $\textcolor{darkorange}{t}$ years, ${\color{#0000FF}{P}}$ is the principal amount invested, ${\color{#FF0000}{r}}$ is the annual interest rate, and ${\color{#009600}{n}}$ is the number of compounding periods each year. $\begin{gathered} y={\color{#0000FF}{P}}\left(1+\dfrac{{\color{#FF0000}{r}}}{{\color{#009600}{n}}}\right)^{{\color{#009600}{n}}\textcolor{darkorange}{t}} \end{gathered}$ In our case, we know that $\textcolor{darkorange}{t}=\textcolor{darkorange}{7},$ ${\color{#0000FF}{P}}={\color{#0000FF}{700}},$ and ${\color{#FF0000}{r}}={\color{#FF0000}{4.3\%}}={\color{#FF0000}{0.043}}.$ Since there are $12$ months in one year, the number of compounding periods is ${\color{#009600}{n}}={\color{#009600}{12}}.$ Let's substitute these values into the compound interest formula and calculate the balance after $\textcolor{darkorange}{7}$ years in our deposit.
$y={\color{#0000FF}{P}}\left(1+\dfrac{{\color{#FF0000}{r}}}{{\color{#009600}{n}}}\right)^{{\color{#009600}{n}}\textcolor{darkorange}{t}}$
$y={\color{#0000FF}{700}}\left(1+\dfrac{{\color{#FF0000}{0.043}}}{{\color{#009600}{12}}}\right)^{{\color{#009600}{12}}\cdot \textcolor{darkorange}{7}}$
$y\approx 945.34$
We found that, after $7$ years, the balance will be around $\ 945.34.$