Envision Math 2.0: Grade 8, Volume 1
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Envision Math 2.0: Grade 8, Volume 1 View details
2. Solve Equations with Variables on Both Sides
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Exercise 13 Page 95

Mark the number of months as x. Describe the populations of both towns in terms of x to make an equation.

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Practice makes perfect
A town's population is 43 425. We are told that about 125 people move out each month, and on average 200 people move in. A nearby town has a population of 45 000. It has no one moving in and an average of 150 people moving away every months. We want to find in about how many months the populations of these two towns will be equal. Let's start with defining x. x - the number of months Let's now express the first and second town's populations in terms of x. The first town has a population of 43 425 minus 125 each month and plus 200 people each month. Therefore, its population will be 43 425 minus the amount of months x multiplied by 125 plus x multiplied by 200. The population of the second town will be 45 000 minus the amount of months x, multiplied by 150. First population:& 43 425- 125x+ 200x Second population:& 45 000- 150x We want these populations to be equal, so we need to make an equation that will have the first population on the left-hand side and the second population on the right-hand side. 43 425- 125x+ 200x = 45 000- 150x Now, we will solve the obtained equation. We will use inverse operations to combine like terms on both sides of the equals sign and solve for x.
43 425-125x+200x = 45 000-150x
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Solve for x
43 425+75x = 45 000-150x
43 425+75x+ 150x = 45 000-150x+ 150x
43 425+225x = 45 000
43 425- 43 425+225x=45 000- 43 425
225x=1 575
225x Ă· 225 = 1 575 Ă· 225
x=7
The populations of the two towns will be equal after about 7 months.