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Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.
x=5/2
To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using inverse operations. In this case, we need to start by adding 25x to both sides of the equation to isolate the x-terms on the right side.
LHS+ 2/5x=RHS+ 2/5x
a/b=a * 5/b * 5
a/b=a * 3/b * 3
Multiply
Commutative Property of Addition
a/c* b = a* b/c
Put minus sign in numerator
Add fractions
Add terms
LHS- 1/3=RHS- 1/3
a = 3* a/3
Multiply
Subtract fractions
Subtract terms
Finally, we can multiply both sides of the equation by 1516. It is an inverse of the fraction standing next to the variable.
LHS * 15/16=RHS* 15/16
Commutative Property of Multiplication
a/b* b/a=1
Multiply fractions
Multiply
a/b=.a /24./.b /24.
Rearrange equation
The solution to the equation is x= 52.