Exercise 6 Page 94

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using inverse operations. In this case, we need to start by adding 25x to both sides of the equation to isolate the x-terms on the right side. Now, we will subtract 13 from both sides of the equation to isolate the constant terms on its left-hand side.

3=16x/15+1/3

SubEqn

LHS- 1/3=RHS- 1/3

3- 1/3=16x/15+1/3- 1/3

▼

Simplify

NumberToFrac

a = 3* a/3

3* 3/3-1/3=16x/15+1/3-1/3

Multiply

Multiply

9/3-1/3=16x/15+1/3-1/3

SubFrac

Subtract fractions

9-1/3=16x/15+1-1/3

SubTerms

Subtract terms

8/3=16x/15

Finally, we can multiply both sides of the equation by 1516. It is an inverse of the fraction standing next to the variable.

8/3=16x/15

MultEqn

LHS * 15/16=RHS* 15/16

8/3* 15/16=16x/15* 15/16

▼

Multiply fractions

CommutativePropMult

Commutative Property of Multiplication

8/3* 15/16=16/15* 15/16* x

MultFracByInverse

a/b* b/a=1

8/3* 15/16=1* x

MultFrac

Multiply fractions

8* 15/3* 16=1* x

Multiply

Multiply

120/48=x

ReduceFrac

a/b=.a /24./.b /24.

5/2=x

RearrangeEqn

Rearrange equation

x=5/2

The solution to the equation is x= 52.