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Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.
b=6
To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using inverse operations. In this case, we need to start by adding 2.6b to both sides of the equation to isolate the b-terms on the right-hand side.
LHS+ 2.6b=RHS+ 2.6b
Commutative Property of Addition
Add terms
Finally, to solve the equation we should divide both sides by the number standing next to the variable. To avoid division by a decimal, we will first multiply both sides of the equation by 2.
LHS * 2=RHS* 2
Commutative Property of Multiplication
Multiply
.LHS / 7.=.RHS / 7.
Calculate quotient
Rearrange equation
The solution to the equation is b=6.